Learn on PengiOpenStax Algebra and TrigonometryChapter 9: Trigonometric Identities and Equations

Lesson 9.1: Verifying Trigonometric Identities and Using Trigonometric Identities to Simplify Trigonometric Expressions

In this Grade 7 lesson from OpenStax Algebra and Trigonometry, students learn how to verify and apply fundamental trigonometric identities, including the Pythagorean identities, reciprocal identities, quotient identities, and even-odd identities. The lesson covers algebraic techniques such as factoring, expanding expressions, and finding common denominators to simplify trigonometric expressions. Students practice rewriting complex trigonometric expressions by transforming one side of an equation into an equivalent form using these core identities.

Section 1

📘 Verifying Trigonometric Identities and Using Trigonometric Identities to Simplify Trigonometric Expressions

New Concept

This lesson introduces trigonometric identities—the fundamental rules of trigonometry. You'll learn to use these identities, like the Pythagorean and even-odd rules, to verify trigonometric statements and simplify complex expressions using algebraic strategies.

What’s next

Next up, you'll see these identities in action through interactive examples. Then, you'll master simplification and verification with a series of practice cards.

Section 2

Pythagorean Identities

Property

The Pythagorean identities are equations involving trigonometric functions based on the properties of a right triangle. The second and third identities can be obtained by manipulating the first.

sin⁡2θ+cos⁡2θ=1 \sin^2 \theta + \cos^2 \theta = 1
1+cot⁡2θ=csc⁡2θ 1 + \cot^2 \theta = \csc^2 \theta
1+tan⁡2θ=sec⁡2θ 1 + \tan^2 \theta = \sec^2 \theta

Examples

  • To simplify csc⁡2θ−cot⁡2θ\csc^2 \theta - \cot^2 \theta, we use the identity 1+cot⁡2θ=csc⁡2θ1 + \cot^2 \theta = \csc^2 \theta. Substituting gives (1+cot⁡2θ)−cot⁡2θ=1(1 + \cot^2 \theta) - \cot^2 \theta = 1.
  • To verify the identity sec⁡2θ−1sec⁡2θ=sin⁡2θ\frac{\sec^2 \theta - 1}{\sec^2 \theta} = \sin^2 \theta, we can substitute tan⁡2θ\tan^2 \theta for sec⁡2θ−1\sec^2 \theta - 1. This gives tan⁡2θsec⁡2θ=sin⁡2θ/cos⁡2θ1/cos⁡2θ=sin⁡2θ\frac{\tan^2 \theta}{\sec^2 \theta} = \frac{\sin^2 \theta / \cos^2 \theta}{1 / \cos^2 \theta} = \sin^2 \theta.
  • To rewrite sin⁡2θ\sin^2 \theta in terms of cos⁡θ\cos \theta, we use sin⁡2θ+cos⁡2θ=1\sin^2 \theta + \cos^2 \theta = 1. Rearranging gives sin⁡2θ=1−cos⁡2θ\sin^2 \theta = 1 - \cos^2 \theta.

Explanation

These powerful identities come from the Pythagorean theorem (a2+b2=c2a^2 + b^2 = c^2) applied to the unit circle. They are essential for rewriting expressions, like converting between sin⁡2θ\sin^2\theta and cos⁡2θ\cos^2\theta, to simplify or solve equations.

Section 3

Even-Odd Identities

Property

The even-odd identities relate the value of a trigonometric function at a given angle to the value of the function at the opposite angle. An even function is one in which f(−x)=f(x)f(-x) = f(x), and an odd function is one in which f(−x)=−f(x)f(-x) = -f(x).

tan⁡(−θ)=−tan⁡θ \tan(-\theta) = -\tan \theta
cot⁡(−θ)=−cot⁡θ \cot(-\theta) = -\cot \theta
sin⁡(−θ)=−sin⁡θ \sin(-\theta) = -\sin \theta
csc⁡(−θ)=−csc⁡θ \csc(-\theta) = -\csc \theta
cos⁡(−θ)=cos⁡θ \cos(-\theta) = \cos \theta
sec⁡(−θ)=sec⁡θ \sec(-\theta) = \sec \theta

Examples

  • To simplify tan⁡(−x)cos⁡(−x)\tan(-x) \cos(-x), we use the identities to get (−tan⁡x)(cos⁡x)=−sin⁡xcos⁡x(cos⁡x)=−sin⁡x(-\tan x)(\cos x) = -\frac{\sin x}{\cos x}(\cos x) = -\sin x.
  • To verify (1+cos⁡x)[1+cos⁡(−x)]=(1+cos⁡x)2(1 + \cos x)[1 + \cos(-x)] = (1+\cos x)^2, we work on the left side: (1+cos⁡x)(1+cos⁡x)=(1+cos⁡x)2(1 + \cos x)(1 + \cos x) = (1 + \cos x)^2.
  • To evaluate sin⁡(−π6)\sin(-\frac{\pi}{6}), we use the odd identity for sine: sin⁡(−π6)=−sin⁡(π6)=−12\sin(-\frac{\pi}{6}) = -\sin(\frac{\pi}{6}) = -\frac{1}{2}.

Explanation

Remember that cosine and its reciprocal, secant, are the only even functions; they 'absorb' the negative sign. The other four functions are odd and pass the negative sign out front. This is useful for simplifying expressions with negative angles.

Section 4

Reciprocal Identities

Property

The reciprocal identities relate trigonometric functions that are reciprocals of each other. They are derived from the definitions of the basic trigonometric functions.

sin⁡θ=1csc⁡θ \sin \theta = \frac{1}{\csc \theta}
cos⁡θ=1sec⁡θ \cos \theta = \frac{1}{\sec \theta}
tan⁡θ=1cot⁡θ \tan \theta = \frac{1}{\cot \theta}
csc⁡θ=1sin⁡θ \csc \theta = \frac{1}{\sin \theta}
sec⁡θ=1cos⁡θ \sec \theta = \frac{1}{\cos \theta}
cot⁡θ=1tan⁡θ \cot \theta = \frac{1}{\tan \theta}

Examples

  • To simplify tan⁡xcot⁡x\tan x \cot x, we substitute 1tan⁡x\frac{1}{\tan x} for cot⁡x\cot x, which gives tan⁡x(1tan⁡x)=1\tan x (\frac{1}{\tan x}) = 1.
  • To rewrite 1cos⁡θ\frac{1}{\cos \theta} as a single function, we use the reciprocal identity to get sec⁡θ\sec \theta.
  • To simplify sec⁡αcsc⁡α\frac{\sec \alpha}{\csc \alpha}, we can write it as 1/cos⁡α1/sin⁡α=1cos⁡α⋅sin⁡α1=tan⁡α\frac{1/\cos \alpha}{1/\sin \alpha} = \frac{1}{\cos \alpha} \cdot \frac{\sin \alpha}{1} = \tan \alpha.

Explanation

Think of these as function pairs that flip upside down. Sine and cosecant are a pair, cosine and secant are a pair, and tangent and cotangent are a pair. This allows you to switch between them to simplify expressions.

Section 5

Quotient Identities

Property

The quotient identities define relationships among certain trigonometric functions and can be very helpful in verifying other identities. They are derived from the definitions of the basic trigonometric functions.

tan⁡θ=sin⁡θcos⁡θ \tan \theta = \frac{\sin \theta}{\cos \theta}
cot⁡θ=cos⁡θsin⁡θ \cot \theta = \frac{\cos \theta}{\sin \theta}

Examples

  • To verify cot⁡θsin⁡θ=cos⁡θ\cot \theta \sin \theta = \cos \theta, we substitute for cot⁡θ\cot \theta: (cos⁡θsin⁡θ)sin⁡θ=cos⁡θ(\frac{\cos \theta}{\sin \theta}) \sin \theta = \cos \theta.
  • To simplify tan⁡xcsc⁡x\tan x \csc x, we rewrite everything in terms of sine and cosine: (sin⁡xcos⁡x)(1sin⁡x)=1cos⁡x=sec⁡x(\frac{\sin x}{\cos x}) (\frac{1}{\sin x}) = \frac{1}{\cos x} = \sec x.
  • To rewrite cot⁡θ+tan⁡θ\cot \theta + \tan \theta as a single fraction: cos⁡θsin⁡θ+sin⁡θcos⁡θ=cos⁡2θ+sin⁡2θsin⁡θcos⁡θ=1sin⁡θcos⁡θ\frac{\cos \theta}{\sin \theta} + \frac{\sin \theta}{\cos \theta} = \frac{\cos^2 \theta + \sin^2 \theta}{\sin \theta \cos \theta} = \frac{1}{\sin \theta \cos \theta}.

Explanation

These identities are your go-to move for breaking down tangent and cotangent into the fundamental building blocks of sine and cosine. This is often the first step in simplifying a complex expression or proving another identity.

Section 6

Verifying Trigonometric Identities

Property

To verify an identity, transform one side of the equation until it is the same as the other side.

  1. Start with the more complex side.
  2. Look for chances to factor, add fractions, or square binomials.
  3. Use known identities to make substitutions.
  4. If stuck, try converting all terms to sines and cosines.

Examples

  • Verify (sin⁡x+cos⁡x)2=1+2sin⁡xcos⁡x(\sin x + \cos x)^2 = 1 + 2\sin x \cos x. Expanding the left side gives sin⁡2x+2sin⁡xcos⁡x+cos⁡2x\sin^2 x + 2\sin x \cos x + \cos^2 x. Since sin⁡2x+cos⁡2x=1\sin^2 x + \cos^2 x = 1, this simplifies to 1+2sin⁡xcos⁡x1 + 2\sin x \cos x.
  • Verify cos⁡x(tan⁡x−sec⁡(−x))=sin⁡x−1\cos x (\tan x - \sec(-x)) = \sin x - 1. The left side is cos⁡x(sin⁡xcos⁡x−sec⁡x)=cos⁡x(sin⁡x−1cos⁡x)=sin⁡x−1\cos x (\frac{\sin x}{\cos x} - \sec x) = \cos x (\frac{\sin x - 1}{\cos x}) = \sin x - 1.
  • Verify cos⁡x−cos⁡3x=cos⁡xsin⁡2x\cos x - \cos^3 x = \cos x \sin^2 x. Factoring the left side gives cos⁡x(1−cos⁡2x)\cos x (1 - \cos^2 x). Using the Pythagorean identity, this becomes cos⁡x(sin⁡2x)\cos x (\sin^2 x).

Explanation

Verifying an identity is like solving a puzzle. You are not solving for a variable, but proving two expressions are always equal. Use algebra and other identities to transform one side until it perfectly matches the other side.

Section 7

Simplify with Algebra

Property

Algebraic patterns can simplify trigonometric expressions.
Difference of Squares: An expression like a2−b2=(a−b)(a+b)a^2 - b^2 = (a-b)(a+b) can apply to expressions such as sin⁡2x−1\sin^2 x - 1 or 4sec⁡2θ−94\sec^2\theta - 9.
Quadratic Form: An expression like 2cos⁡2θ+cos⁡θ−12\cos^2 \theta + \cos \theta - 1 is in the form 2x2+x−12x^2 + x - 1 where x=cos⁡θx = \cos \theta, and can be factored.

Examples

  • Rewrite 9cos⁡2θ−19\cos^2 \theta - 1 using the difference of squares. This is (3cos⁡θ)2−12(3\cos \theta)^2 - 1^2, which factors to (3cos⁡θ−1)(3cos⁡θ+1)(3\cos \theta - 1)(3\cos \theta + 1).
  • Factor 2sin⁡2θ+sin⁡θ−12\sin^2 \theta + \sin \theta - 1. Letting x=sin⁡θx = \sin \theta, the expression becomes 2x2+x−12x^2 + x - 1, which factors to (2x−1)(x+1)(2x - 1)(x + 1). So, the original expression is (2sin⁡θ−1)(sin⁡θ+1)(2\sin \theta - 1)(\sin \theta + 1).
  • Simplify (sec⁡x+1)(sec⁡x−1)(\sec x + 1)(\sec x - 1). This follows the difference of squares pattern, resulting in sec⁡2x−1\sec^2 x - 1, which simplifies to tan⁡2x\tan^2 x by the Pythagorean identity.

Explanation

Don't forget your algebra skills! Recognizing familiar patterns like the difference of squares or quadratic equations is a secret weapon. It makes complex-looking trigonometric problems much easier to factor, simplify, and solve.

Book overview

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Chapter 9: Trigonometric Identities and Equations

  1. Lesson 1Current

    Lesson 9.1: Verifying Trigonometric Identities and Using Trigonometric Identities to Simplify Trigonometric Expressions

  2. Lesson 2

    Lesson 9.2: Sum and Difference Identities

  3. Lesson 3

    Lesson 9.3 : Double-Angle, Half-Angle, and Reduction Formulas

  4. Lesson 4

    Lesson 9.5 : Solving Trigonometric Equations

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 Verifying Trigonometric Identities and Using Trigonometric Identities to Simplify Trigonometric Expressions

New Concept

This lesson introduces trigonometric identities—the fundamental rules of trigonometry. You'll learn to use these identities, like the Pythagorean and even-odd rules, to verify trigonometric statements and simplify complex expressions using algebraic strategies.

What’s next

Next up, you'll see these identities in action through interactive examples. Then, you'll master simplification and verification with a series of practice cards.

Section 2

Pythagorean Identities

Property

The Pythagorean identities are equations involving trigonometric functions based on the properties of a right triangle. The second and third identities can be obtained by manipulating the first.

sin⁡2θ+cos⁡2θ=1 \sin^2 \theta + \cos^2 \theta = 1
1+cot⁡2θ=csc⁡2θ 1 + \cot^2 \theta = \csc^2 \theta
1+tan⁡2θ=sec⁡2θ 1 + \tan^2 \theta = \sec^2 \theta

Examples

  • To simplify csc⁡2θ−cot⁡2θ\csc^2 \theta - \cot^2 \theta, we use the identity 1+cot⁡2θ=csc⁡2θ1 + \cot^2 \theta = \csc^2 \theta. Substituting gives (1+cot⁡2θ)−cot⁡2θ=1(1 + \cot^2 \theta) - \cot^2 \theta = 1.
  • To verify the identity sec⁡2θ−1sec⁡2θ=sin⁡2θ\frac{\sec^2 \theta - 1}{\sec^2 \theta} = \sin^2 \theta, we can substitute tan⁡2θ\tan^2 \theta for sec⁡2θ−1\sec^2 \theta - 1. This gives tan⁡2θsec⁡2θ=sin⁡2θ/cos⁡2θ1/cos⁡2θ=sin⁡2θ\frac{\tan^2 \theta}{\sec^2 \theta} = \frac{\sin^2 \theta / \cos^2 \theta}{1 / \cos^2 \theta} = \sin^2 \theta.
  • To rewrite sin⁡2θ\sin^2 \theta in terms of cos⁡θ\cos \theta, we use sin⁡2θ+cos⁡2θ=1\sin^2 \theta + \cos^2 \theta = 1. Rearranging gives sin⁡2θ=1−cos⁡2θ\sin^2 \theta = 1 - \cos^2 \theta.

Explanation

These powerful identities come from the Pythagorean theorem (a2+b2=c2a^2 + b^2 = c^2) applied to the unit circle. They are essential for rewriting expressions, like converting between sin⁡2θ\sin^2\theta and cos⁡2θ\cos^2\theta, to simplify or solve equations.

Section 3

Even-Odd Identities

Property

The even-odd identities relate the value of a trigonometric function at a given angle to the value of the function at the opposite angle. An even function is one in which f(−x)=f(x)f(-x) = f(x), and an odd function is one in which f(−x)=−f(x)f(-x) = -f(x).

tan⁡(−θ)=−tan⁡θ \tan(-\theta) = -\tan \theta
cot⁡(−θ)=−cot⁡θ \cot(-\theta) = -\cot \theta
sin⁡(−θ)=−sin⁡θ \sin(-\theta) = -\sin \theta
csc⁡(−θ)=−csc⁡θ \csc(-\theta) = -\csc \theta
cos⁡(−θ)=cos⁡θ \cos(-\theta) = \cos \theta
sec⁡(−θ)=sec⁡θ \sec(-\theta) = \sec \theta

Examples

  • To simplify tan⁡(−x)cos⁡(−x)\tan(-x) \cos(-x), we use the identities to get (−tan⁡x)(cos⁡x)=−sin⁡xcos⁡x(cos⁡x)=−sin⁡x(-\tan x)(\cos x) = -\frac{\sin x}{\cos x}(\cos x) = -\sin x.
  • To verify (1+cos⁡x)[1+cos⁡(−x)]=(1+cos⁡x)2(1 + \cos x)[1 + \cos(-x)] = (1+\cos x)^2, we work on the left side: (1+cos⁡x)(1+cos⁡x)=(1+cos⁡x)2(1 + \cos x)(1 + \cos x) = (1 + \cos x)^2.
  • To evaluate sin⁡(−π6)\sin(-\frac{\pi}{6}), we use the odd identity for sine: sin⁡(−π6)=−sin⁡(π6)=−12\sin(-\frac{\pi}{6}) = -\sin(\frac{\pi}{6}) = -\frac{1}{2}.

Explanation

Remember that cosine and its reciprocal, secant, are the only even functions; they 'absorb' the negative sign. The other four functions are odd and pass the negative sign out front. This is useful for simplifying expressions with negative angles.

Section 4

Reciprocal Identities

Property

The reciprocal identities relate trigonometric functions that are reciprocals of each other. They are derived from the definitions of the basic trigonometric functions.

sin⁡θ=1csc⁡θ \sin \theta = \frac{1}{\csc \theta}
cos⁡θ=1sec⁡θ \cos \theta = \frac{1}{\sec \theta}
tan⁡θ=1cot⁡θ \tan \theta = \frac{1}{\cot \theta}
csc⁡θ=1sin⁡θ \csc \theta = \frac{1}{\sin \theta}
sec⁡θ=1cos⁡θ \sec \theta = \frac{1}{\cos \theta}
cot⁡θ=1tan⁡θ \cot \theta = \frac{1}{\tan \theta}

Examples

  • To simplify tan⁡xcot⁡x\tan x \cot x, we substitute 1tan⁡x\frac{1}{\tan x} for cot⁡x\cot x, which gives tan⁡x(1tan⁡x)=1\tan x (\frac{1}{\tan x}) = 1.
  • To rewrite 1cos⁡θ\frac{1}{\cos \theta} as a single function, we use the reciprocal identity to get sec⁡θ\sec \theta.
  • To simplify sec⁡αcsc⁡α\frac{\sec \alpha}{\csc \alpha}, we can write it as 1/cos⁡α1/sin⁡α=1cos⁡α⋅sin⁡α1=tan⁡α\frac{1/\cos \alpha}{1/\sin \alpha} = \frac{1}{\cos \alpha} \cdot \frac{\sin \alpha}{1} = \tan \alpha.

Explanation

Think of these as function pairs that flip upside down. Sine and cosecant are a pair, cosine and secant are a pair, and tangent and cotangent are a pair. This allows you to switch between them to simplify expressions.

Section 5

Quotient Identities

Property

The quotient identities define relationships among certain trigonometric functions and can be very helpful in verifying other identities. They are derived from the definitions of the basic trigonometric functions.

tan⁡θ=sin⁡θcos⁡θ \tan \theta = \frac{\sin \theta}{\cos \theta}
cot⁡θ=cos⁡θsin⁡θ \cot \theta = \frac{\cos \theta}{\sin \theta}

Examples

  • To verify cot⁡θsin⁡θ=cos⁡θ\cot \theta \sin \theta = \cos \theta, we substitute for cot⁡θ\cot \theta: (cos⁡θsin⁡θ)sin⁡θ=cos⁡θ(\frac{\cos \theta}{\sin \theta}) \sin \theta = \cos \theta.
  • To simplify tan⁡xcsc⁡x\tan x \csc x, we rewrite everything in terms of sine and cosine: (sin⁡xcos⁡x)(1sin⁡x)=1cos⁡x=sec⁡x(\frac{\sin x}{\cos x}) (\frac{1}{\sin x}) = \frac{1}{\cos x} = \sec x.
  • To rewrite cot⁡θ+tan⁡θ\cot \theta + \tan \theta as a single fraction: cos⁡θsin⁡θ+sin⁡θcos⁡θ=cos⁡2θ+sin⁡2θsin⁡θcos⁡θ=1sin⁡θcos⁡θ\frac{\cos \theta}{\sin \theta} + \frac{\sin \theta}{\cos \theta} = \frac{\cos^2 \theta + \sin^2 \theta}{\sin \theta \cos \theta} = \frac{1}{\sin \theta \cos \theta}.

Explanation

These identities are your go-to move for breaking down tangent and cotangent into the fundamental building blocks of sine and cosine. This is often the first step in simplifying a complex expression or proving another identity.

Section 6

Verifying Trigonometric Identities

Property

To verify an identity, transform one side of the equation until it is the same as the other side.

  1. Start with the more complex side.
  2. Look for chances to factor, add fractions, or square binomials.
  3. Use known identities to make substitutions.
  4. If stuck, try converting all terms to sines and cosines.

Examples

  • Verify (sin⁡x+cos⁡x)2=1+2sin⁡xcos⁡x(\sin x + \cos x)^2 = 1 + 2\sin x \cos x. Expanding the left side gives sin⁡2x+2sin⁡xcos⁡x+cos⁡2x\sin^2 x + 2\sin x \cos x + \cos^2 x. Since sin⁡2x+cos⁡2x=1\sin^2 x + \cos^2 x = 1, this simplifies to 1+2sin⁡xcos⁡x1 + 2\sin x \cos x.
  • Verify cos⁡x(tan⁡x−sec⁡(−x))=sin⁡x−1\cos x (\tan x - \sec(-x)) = \sin x - 1. The left side is cos⁡x(sin⁡xcos⁡x−sec⁡x)=cos⁡x(sin⁡x−1cos⁡x)=sin⁡x−1\cos x (\frac{\sin x}{\cos x} - \sec x) = \cos x (\frac{\sin x - 1}{\cos x}) = \sin x - 1.
  • Verify cos⁡x−cos⁡3x=cos⁡xsin⁡2x\cos x - \cos^3 x = \cos x \sin^2 x. Factoring the left side gives cos⁡x(1−cos⁡2x)\cos x (1 - \cos^2 x). Using the Pythagorean identity, this becomes cos⁡x(sin⁡2x)\cos x (\sin^2 x).

Explanation

Verifying an identity is like solving a puzzle. You are not solving for a variable, but proving two expressions are always equal. Use algebra and other identities to transform one side until it perfectly matches the other side.

Section 7

Simplify with Algebra

Property

Algebraic patterns can simplify trigonometric expressions.
Difference of Squares: An expression like a2−b2=(a−b)(a+b)a^2 - b^2 = (a-b)(a+b) can apply to expressions such as sin⁡2x−1\sin^2 x - 1 or 4sec⁡2θ−94\sec^2\theta - 9.
Quadratic Form: An expression like 2cos⁡2θ+cos⁡θ−12\cos^2 \theta + \cos \theta - 1 is in the form 2x2+x−12x^2 + x - 1 where x=cos⁡θx = \cos \theta, and can be factored.

Examples

  • Rewrite 9cos⁡2θ−19\cos^2 \theta - 1 using the difference of squares. This is (3cos⁡θ)2−12(3\cos \theta)^2 - 1^2, which factors to (3cos⁡θ−1)(3cos⁡θ+1)(3\cos \theta - 1)(3\cos \theta + 1).
  • Factor 2sin⁡2θ+sin⁡θ−12\sin^2 \theta + \sin \theta - 1. Letting x=sin⁡θx = \sin \theta, the expression becomes 2x2+x−12x^2 + x - 1, which factors to (2x−1)(x+1)(2x - 1)(x + 1). So, the original expression is (2sin⁡θ−1)(sin⁡θ+1)(2\sin \theta - 1)(\sin \theta + 1).
  • Simplify (sec⁡x+1)(sec⁡x−1)(\sec x + 1)(\sec x - 1). This follows the difference of squares pattern, resulting in sec⁡2x−1\sec^2 x - 1, which simplifies to tan⁡2x\tan^2 x by the Pythagorean identity.

Explanation

Don't forget your algebra skills! Recognizing familiar patterns like the difference of squares or quadratic equations is a secret weapon. It makes complex-looking trigonometric problems much easier to factor, simplify, and solve.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 9: Trigonometric Identities and Equations

  1. Lesson 1Current

    Lesson 9.1: Verifying Trigonometric Identities and Using Trigonometric Identities to Simplify Trigonometric Expressions

  2. Lesson 2

    Lesson 9.2: Sum and Difference Identities

  3. Lesson 3

    Lesson 9.3 : Double-Angle, Half-Angle, and Reduction Formulas

  4. Lesson 4

    Lesson 9.5 : Solving Trigonometric Equations